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-4x^2-64x-240=0
a = -4; b = -64; c = -240;
Δ = b2-4ac
Δ = -642-4·(-4)·(-240)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-16}{2*-4}=\frac{48}{-8} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+16}{2*-4}=\frac{80}{-8} =-10 $
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